At $0^{o}$ C, the density of a certain oxide of a gas at $2$ bar is same as that of dinitrogen at $5$ bar. What is the molecular mass of the oxide?

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Solution

We know that :

$d = \frac{M P}{R T}$

At same density and same temperature,

$M_{1} P_{1} = M_{2} P_{2} (R i s c o n s t a n t) - (1)$

where,
$p_{1} = 2 b a r$

$M_{2} = N_{2} = 28$

putting these value in equation (1)

$M_{1} \times 2 = 28 \times 5$

$M_{1} = 70$

Thus mass of the oxide is 70 g/mol.

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