At $0^{o} C$ , if enthalpy of vapourisation of ice is 40.65 $k J / m o l$ . the molar entropy change for melting of ice at $0^{o} C$ is $k J / m o l$ .

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Solution

Change in entropy for a phase transformation is given as:
$△ S_{t r a n s f o r m a t i o n} = \frac{△ H_{t r a n s f o r m a t i o n}}{T}$

putting all the values from question we get:

$△ S_{f u s i o n} = \frac{△ H_{f u s i o n}}{T}$

$△ S_{f u s i o n} = \frac{40.65}{273}$

$△ S_{f u s i o n} = 0.148 k J / m o l$

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