At 0°C temperature and constant pressure volume of a gas of fixed mass is 2 lit. Now keeping pressure constant the temperature has been raised to 546°С. Find out the final volume of the gas?
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Solution
According to Charles' law, Vθ=V0(1+θ273]WhereV0=volumeofgasat0°C=2lit,θ=finaltemperature=546°C,Vθ=finalvolumeofthegas=?∴Vθ=2(1+546273]lit=(2×3)lit=6lit.