Question

At ${10}^{o}C$, the osmotic pressure of urea solution is $500mm$. The solution is diluted and the temperature is raised to ${25}^{o}C$, the osmotic pressure is found to be found to be $105.3mm$. Determine the extent of dilution.

Answer 1

$P_1=500mm$

$P_2=105.3mm$

$T_1=283K$

$T_2=298K$

Now, $\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}\Rightarrow \frac{V_2}{V_1}=\frac{P_1{T}_2}{{P_{2}T}_1}=\frac{500\times 298}{105.3\times 283}\Rightarrow \frac{V_2}{V_1}=5$

Answer: $5times$