Question

At ${100}^{0}C$ and 1 atmp, if the density of liquid water is 1.0g ${cm}^{-3}$ and that of water vapour is 0.0006g ${cm}^{-3}$, then the volume occupied by water molecules in 1 L of steam at the temperature is:

• A. 6 ${cm}^3$
• B. 60 ${cm}^3$
• C. 0.6 ${cm}^3$
• D. 0.06 ${cm}^3$

Answer 1

Answer: (C)

0.6 ${cm}^3$

Let $1.0L$ of liquid water is converted into steam

Volume of $1000g$ of steam= $\frac{1000}{0.0006}c{m}^3$

$\because$ Volume of water molecules in ${\left(1000/0.0006\right)}^{c{m}^3}$ steam

$\therefore$ Volume of water molecules in $1000c{m}^3$ steam,

$=\frac{0.0006\times 1000\times 1000}{1000}$

$=0.6c{m}^3$