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Question

At 1000C the vapour pressure of a solution of 6.5 g of a solute in 100 g water is 732 mm. If Kb=0.52, the boiling point of this solution will be:

A
1020C
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B
1030C
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C
1010C
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D
1000C
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Solution

The correct option is C 1010C
Given: WB=6.5g,WA=100g,ps=732 mm,Kb=0.52,T0b=1000C,p0=760 mm

P0PsP0=n2n1760732760=n2100/18

n2=28×100760×18=0.2046 mol
ΔTb=Kb×m
TbT0b=Kb×n2×1000WA(g)
Tb1000 C=0.52×0.2046×1000100=1.06
Tb=100+1.06=101.060 C

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