wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

At 100C, benzene & toluene have vapour pressure of 1375 & 558 Torr respectively. Assuming these two form an ideal binary solution, calculate the composition of lthe solution that boils at 1 atm & 100C. What is the composition of vapour issuing at these conditions?

A
xb=0.2472,Yb=0.4473
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
xb=0.4473,Yb=0.2472
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
xb=0.362,Yb=0.321
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
None of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A xb=0.2472,Yb=0.4473
Let XB and XT be the mole fractions of benzene and toluene in solution.
XT=1XB
Ptotal=PB+PT
Ptotal is the total pressure of the mixture. It is 1 atm or 760 torr.
PB is the partial pressure of benzene. PT is partial pressure of toluene.
PB=XBPoB=XB(1375)
PT=XTPoT=(1XB)558
Ptotal=760=(1375)XB+558(1XB)
760=(817)XB+558
(817)XB=202
XB=0.2472
XT=1XB=0.7528
Let YB and YT be the mole fractions of benzene and toluene in the vapour phase.
YB=PBPtotal=1375×0.2472760=0.4473
YT=10.4473=0.5527

flag
Suggest Corrections
thumbs-up
0
similar_icon
Similar questions
View More
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Equations Redefined
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon