Question

At ${100}^{o}C$ and $1$ atm, if the density of liquid water is $1.0g$ ${cm}^{-3}$ and that of water vapour is $0.0006g$ ${cm}^{-3}$, then the volume occupied by water molecules in $1$ litre of steam at that temperature is:

• A. $6{cm}^3$
• B. $60{cm}^3$
• C. $0.6{cm}^3$
• D. $0.06{cm}^3$

Answer 1

Answer: (C)

$0.6{cm}^3$

Density of liquid water = $1.0g$ $c{m}^{-3}$

Density of water vapour = $0.0006g$ $c{m}^{-3}$

mass of 1000mL stream =$\frac{massof1000mLstream}{Densityofliquidwater}=\frac{0.6gm}{1gmc{m}^{-3}}$

$\therefore$ volume of liquid water = $0.6$ $c{m}^{-3}$

Hence, option (C) is the correct answer.