Question

At ${100}^o\text{C}$ and $1$ atm, if the density of the liquid water is $1.0$ g/cc and that of water vapour is $0.00006$ g/cc, then the volume occupied by water molecule in $1$ L steam at this temperature is :

• A. $6$ cc
• B. $60$ cc
• C. $0.6$ cc
• D. $0.06$ cc

Answer 1

The correct option is D $0.06$ cc

Mass of water in $1$ L steam $=1000\times 0.00006$ g $=0.06$ g
Volume of $0.06$ g water $=\frac{0.06}{1}=0.06$ cc