Question

At ${100}^{o}C$ and 1 $atm$, if the density of liquid water is $1.0gc{m}^{-3}$ and that of water vapour is $0.0006gc{m}^{-3}$, then the volume occupied by water molecules in one litre of steam at that temperature is:

• A. $6c{m}^3$
• B. $60c{m}^3$
• C. $0.6c{m}^3$
• D. $0.06c{m}^3$

Answer 1

The correct option is C $0.6c{m}^3$

Mass of 1 litre water vapour $=V\times d=1000\times 0.0006=0.6g$
$\therefore$ Volume of liquid water $=\frac{0.6}{1}=0.6c{m}^3$