Question

At ${100}^{o}C$ and 1 $atm$ if the density of the liquid water is 1.0 $gc{m}^{-3}$ and that of water vapour is 0.0006 $gc{m}^{-3}$, then the volume occupied by water molecules in 1 $L$ of steam at this temperature is:

• A. $6c{m}^3$
• B. $60c{m}^3$
• C. $0.6c{m}^3$
• D. $0.06c{m}^3$

Answer 1

Answer: (C)

$0.6c{m}^3$

Mass of $1000mL$ steam = $1000\times 0.0006=0.6gm$

$\therefore$ Volume of liquid water $=\frac{0.6}{1}=0.6c{m}^3$

So the correct answer is option $C$.