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Question

At 1000 K, the value of Kp for the following reaction is 0.05 atm. The value of Kc in terms of R would be?
A(g)+2B(g)3C(g)+D(g)

A
20000 R
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B
0.02 R
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C
5×105 R
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D
5×105R1
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Solution

The correct option is D 5×105R1
Kp=Kc(RT)Δn

Δn=43=1

KP=0.05 atm,T=1000 K

KC=Kp(R×1000=0.05(R×1000)=5×105R1

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