Question

At ${127}^{o}C$ a vessel has certain gas. At same $P$ to what $T$ is must be heated so that half of the gas escapes?

• A. ${600}^{o}C$
• B. ${627}^{o}C$
• C. ${527}^{o}C$
• D. ${800}^{o}C$

Answer 1

The correct option is C ${527}^{o}C$

At constant P, $n\propto \frac{1}{T}$ [since PV=nRT]

$T_1=127℃$=400 K and $T_2=?$

$n_2=0.5n_1$

Now, $T_1{n}_1=T_2{n}_2$

$⟹n_1\times 400K=0.5n_1\times T_2⟹T_2=800K=527℃$

$\therefore$ Vessel should be heated to 800 K so that half of the gas escapes.