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Characteristics of Equilibrium Constant

At 1400 K, fo...

Question

At $1400 K$ , for the reaction $C H_{4} (g) + 2 H_{2} S (g) ⇌ C S_{2} (g) + 4 H_{2} (g)$ , $K_{c} = 2.5 \times 10^{- 3}$ . A $10 L$ reaction vessel contains 2 moles of $C H_{4},$ 3 moles of $C S_{2}$ , 3 moles of $H_{2}$ and 4 moles of $H_{2} S$ . Choose the correct statement from the following:

This reaction is at equilibrium with given concentrations.

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The reaction will proceed in forward direction

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The reaction will proceed in backward direction

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The information is insufficient to decide the direction of progress of reaction

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Solution

The correct option is C The reaction will proceed in backward direction
For the reaction,
$Q_{C} = \frac{{(\frac{n_{H_{2}}}{V})}^{4} (\frac{n_{C S_{2}}}{V})}{(\frac{n_{C H_{4}}}{V}) {(\frac{n_{H_{2} S}}{V})}^{2}}$

putting the values,
$Q_{C} = \frac{{(\frac{3}{10})}^{4} (\frac{3}{10})}{(\frac{2}{10}) {(\frac{4}{10})}^{2}} = \frac{243}{32} \times 10^{- 2} = 7.59 \times 10^{- 2} > K_{c}$

So, reaction will proceed in backward direction.

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Similar questions

Q. At

1400 K

K_{c} = 2.5 \times 10^{- 3}

for the reaction

C H_{4} (g) + 2 H_{2} S (g) ⇌ C S_{2} (g) + 4 H_{2} (g)

. If A

10.0 L

reaction vessel at

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contains

2.0

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3.0

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Q. At

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for reaction

C H_{4} (g) + 2 H_{2} S (g) ⇌ C S_{2} (g) + 4 H_{2} (g)

. At 10.0L reaction vessel at 1400K contains 2.00 mole of CH

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For the reaction $A (g) + 2 B (g) ⇌ 2 (g) + D (s)$ , 2 moles of A, 3 moles of B and 1 mole of C are present in 10L vessel if $K_{C}$ for the reaction is 3.6, the reaction will proceed in:-

Q. At 1400 K,

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Characteristics of Equilibrium Constant

Standard XII Chemistry

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At 1400 K, for the reaction CH4 (g)+2H2S (g)⇌CS2 (g)+4H2 (g), Kc=2.5×10−3. A 10 L reaction vessel contains 2 moles of CH4, 3 moles of CS2 , 3 moles of H2 and 4 moles of H2S. Choose the correct statement from the following:

The correct option is C The reaction will proceed in backward directionFor the reaction, QC=(nH2V)4(nCS2V)(nCH4V)(nH2SV)2 putting the values, QC=(310)4(310)(210)(410)2=24332×10−2=7.59×10−2>Kc So, reaction will proceed in backward direction.

At $1400 K$ , for the reaction $C H_{4} (g) + 2 H_{2} S (g) ⇌ C S_{2} (g) + 4 H_{2} (g)$ , $K_{c} = 2.5 \times 10^{- 3}$ . A $10 L$ reaction vessel contains 2 moles of $C H_{4},$ 3 moles of $C S_{2}$ , 3 moles of $H_{2}$ and 4 moles of $H_{2} S$ . Choose the correct statement from the following: