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Factors Affecting the Rate of a Chemical Reaction

At 248∘C, t...

Question

At $248^{\circ}$ C, the $K_{p}$ for the reaction, $S b C l_{5} (g) \leftrightarrow S b C l_{3} (g) + C l_{2} (g)$ is 1.07 atm at a total pressure of 1 atm. Calculate the degree of dissociation of $S b C l_{5}$ .

0.516

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0.718

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0.321

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None of these

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Solution

The correct option is C 0.718
$K_{P} = \frac{x^{2}}{1 - x^{2}} = 1.07$

$2.07 x^{2} = 1.07$

$x = 0.71$

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