At $25^{\circ} C$ , the standard emf of a cell having reaction involving two electrons change is found to be $0.295 V$ . The equilibrium constant of the reaction is_____________.

29.5 \times 10^{- 2}

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10

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1 \times 10^{10}

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29.5 \times 10^{10}

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Solution

The correct option is C $1 \times 10^{10}$
$Δ G_{0} = - n F E_{0} = - R T ln K n = 2 (g i v e n) 2 \times 96500 \times 0.295 = 8.314 \times 298 \times ln K ln K = 22.9801 K = e^{22.9801} = 1 \times 10^{10}$

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At 25∘C, the standard emf of a cell having reaction involving two electrons change is found to be 0.295 V. The equilibrium constant of the reaction is_____________.

The correct option is C 1×1010ΔG0=−nFE0=−RTlnKn=2(given)2×96500×0.295=8.314×298×lnKlnK=22.9801K=e22.9801=1×1010

At $25^{\circ} C$ , the standard emf of a cell having reaction involving two electrons change is found to be $0.295 V$ . The equilibrium constant of the reaction is_____________.

The correct option is C $1 \times 10^{10}$
$Δ G_{0} = - n F E_{0} = - R T ln K n = 2 (g i v e n) 2 \times 96500 \times 0.295 = 8.314 \times 298 \times ln K ln K = 22.9801 K = e^{22.9801} = 1 \times 10^{10}$