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Introduction of VSEPR

At 25oC 1 mol...

Question

At $25^{o} C$ 1 mole of butane is heated, then $C O_{2} a n d H_{2} O$ liquid is formed, work done is

75.6 L atm

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85.6 L atm

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50.3 L atm

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None of these

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Solution

The correct option is B 85.6 L atm
Correct option is B
$C_{4} H_{10} (g) + \frac{13}{2} O_{2} (g) \to 4 C O_{2} (g) + 5 H_{2} O (l)$

$Δ n_{g} = 4 - (1 + \frac{13}{2})$

$= - \frac{7}{2} m o l$

$Workdone, W = - Δ n_{g} R T$

$= - (- \frac{7}{2} \times 0.0821 \times 298)$
$W = 85.6 L a t m$

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