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Standard XII

Physics

Gas laws from KTG

At 250oC an...

Question

At $250^{o} C$ and $1$ atmosphere pressure, the vapour density of $P C I_{5}$ is $57.9$ . What will be the dissociation of $P C I_{5} -$

1.00

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0.90

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0.80

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0.65

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Solution

The correct option is C $0.80$

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Similar questions

6)The vapour density of PCI₅ is 104.16, but when heated at 230⁰C, its vapour density is reduced to 62. The percentage of dissociation of PCI₅ at this temperature will be:

Q. At

250^{o} C

and

1

atmospheric pressure, the vapour density of

P {C l}_{5}

57.9

Calculate:

(i)

K_{p}

for the reaction,

P {C l}_{5} ⇌ P {C l}_{3} (g) + {C l}_{2} (g)

250^{o} C

(ii) the percentage dissociation when pressure is doubled.

6)The vapour density of PCI₅ is 104.16, but when heated at 230⁰C, its vapour density is reduced to 62. The percentage of dissociation of PCI₅ at this temperature will be:

Q. The degree of dissociation,

α

P C I_{5}

at a given temperature is-

Q. For gaseous decomposition of

{P C I}_{5}

in a closed vessel the degree of dissociation '

α

', equilibrium pressure 'P' &

{^{'} K}_{p}^{'}

are related as

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At 250oC and 1 atmosphere pressure, the vapour density of PCI5 is 57.9 . What will be the dissociation of PCI5−

The correct option is C 0.80

At $250^{o} C$ and $1$ atmosphere pressure, the vapour density of $P C I_{5}$ is $57.9$ . What will be the dissociation of $P C I_{5} -$

The correct option is C $0.80$