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Le Chatelier's Principle for Del N Equals to 0

At 250oC an...

Question

At $250^{o} C$ and 1 atm presser the V.d of $P C l_{5}$ is 57.9
calculate PCl $⇌ P C l_{3} + C l_{2}$
I Kp of rxn
II % dissociation when p is doubled

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Solution

M min = $\frac{M T h e r o r e t i c a l}{1 = (M - 1) x)}$ $P C l_{5} + P C l_{3} + C l_{2}$
57.9 = $\frac{104.25}{1 + x}$ $K p = \frac{X^{2} p}{1 - X^{2}} = \frac{0.64}{0.36} = \frac{16}{9}$
X = 0.8

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