Question

At ${27}^{0}C$ if temperature of $1mol$ of gas is increased by ${50}^{0}C$ the % change in kinetic energy of system is:

• A. $16.67$
• B. $18.57$
• C. $85.18$
• D. $7.66$

Answer 1

Answer: (A)

$16.67$

At ${27}^{o}C$ $K.E=\frac{3}{2}RT$

$K.E=\frac{3}{2}\times 8.314\times 300K=450R$

Change in kinetic energy= $\frac{3}{2}R(350-300)K=75R$

Hence, % change in kinetic energy= $\frac{75R}{450R}\times 100=16.67$%