At 27∘C, a balloon is filled with 3 L air. The volume of the balloon when the temperature is 54∘C is .

3.27 L

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2.75 L

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1.5 L

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6 L

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Solution

The correct option is A 3.27 L
According to Charles' Law at constant pressure the volume of a fixed amount of gas is directly proportional to its temperature-
i.e $V$ α $T$
Thus, $\frac{V_{1}}{T_{1}} = \frac{V_{2}}{T_{2}}$ , where
$V_{1}$ = initial volume; $V_{2}$ = final volume
$T_{1}$ = initial temperature; $T_{2}$ = final temperature
$V_{1}$ = 2 L, $V_{2}$ = ?
$T_{1}$ = 273 + 27 = 300 K
$T_{2}$ = 273 + 54 = 327 K
Therefore, $V_{2} = \frac{V_{1} \times T_{2}}{T_{1}}$ = $\frac{3 \times 327}{300}$ = 3.27 L

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