Question

At ${27}^{\circ }C$ temperature the kinetic energy of an ideal gas is $E_1$ .If the temperature is increased to ${327}^{\circ }C$, then the kinetic energy will be

• A. $\frac{E_1}{\sqrt{2}}$
• B. $\sqrt{2}{E}_1$
• C. $2E_1$
• D. $\frac{E_1}{2}$

Answer 1

The correct option is C $2E_1$

From KTG,
$E=\frac{3}{2}kT\Rightarrow E\propto T$

$\therefore \frac{E_2}{E_1}=\frac{T_2}{T_1}=\frac{600}{300}=2$

$\Rightarrow E_2=2E_1$