At $27^{o} C$ , $500$ $m l$ of helium diffuse in $30$ minutes.What is the time (in hours) taken for $100$ $m l$ of $S O_{2}$ to diffuse under same experimental conditions:

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Solution

The correct option is D $0.4$
$\frac{V_{1} t_{2}}{V_{2} t_{1}} = \sqrt{\frac{M_{2}}{M_{1}}}$

$\frac{500 \times t_{2}}{100 \times 30} = \sqrt{\frac{64}{4}}$

$t_{2} = \frac{120}{5} m i n s$ = $0.4$ $h o u r s$

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At 27oC , 500 ml of helium diffuse in 30 minutes.What is the time (in hours) taken for 100 ml of SO2 to diffuse under same experimental conditions:

The correct option is D 0.4V1t2V2t1=√M2M1500×t2100×30=√644t2=1205mins = 0.4 hours

At $27^{o} C$ , $500$ $m l$ of helium diffuse in $30$ minutes.What is the time (in hours) taken for $100$ $m l$ of $S O_{2}$ to diffuse under same experimental conditions:

The correct option is D $0.4$
$\frac{V_{1} t_{2}}{V_{2} t_{1}} = \sqrt{\frac{M_{2}}{M_{1}}}$

$\frac{500 \times t_{2}}{100 \times 30} = \sqrt{\frac{64}{4}}$

$t_{2} = \frac{120}{5} m i n s$ = $0.4$ $h o u r s$