Question

At $273.15K$ and under a pressure of $10.1325M{P}_a$, the compressibility factor of $O_2$ is $0.927$. Calculate the mass of $O_2$ necessary to fill a gas cylinder of $100d{m}^3$ capacity under the given conditions.

Answer 1

$\frac{PV}{nRT}=Z$

$\frac{10.1325\times {10}^{6}Pa}{\frac{m}{M}\times 8.314\times 273.15}=0.927$

$\frac{4461.75}{\frac{m}{M}}=0.927$

$\frac{4461.75}{0.927}=\frac{m}{M}$

$\frac{4461.75}{0.927}\times 32=M$

$154019.4g=M$.