At 273K temperature and 9atm pressure, the compressibility for gas is 0.9. The volume of 1millimole of gas at this temperature and pressure is :
We know that, compressibility factor for a gas, Z = PVnRT
⇒ V = ZnRTP
Given,
Z=0.9,n=1m.mole,T=273K,P=9atm.
⇒ V = 0.9×1×0.0821×2739 = 2.24mL
Hence, vol. of 1millimole of gas = 2.24mL
Option C is correct.