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Question

At 273K temperature and 9atm pressure, the compressibility for gas is 0.9. The volume of 1millimole of gas at this temperature and pressure is :

A
2.24litre
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B
0.020mL
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C
2.24mL
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D
22.4mL
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Solution

The correct option is C 2.24mL

We know that, compressibility factor for a gas, Z = PVnRT

V = ZnRTP

Given,

Z=0.9,n=1m.mole,T=273K,P=9atm.


V = 0.9×1×0.0821×2739 = 2.24mL


Hence, vol. of 1millimole of gas = 2.24mL

Option C is correct.


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