Question

At 291 K, the equivalent conductivities at infinite dilution of $HCl,NaCl$ and $C{H}_{3}COONa$ are 369.3, 101.7 and 71.7 $Sc{m}^{2}e{q}^{-1}$ respectively. If equivalent conductivity of centinormal solution of acetic acid is 14.3 $Sc{m}^{2}e{q}^{-1}$, $\left[H^{+}\right]$ in solution of acetic acid is $X\times {10}^{-4}$. Value of $X$ is:

Answer 1

As given,

Eq. conductance of $C{H}_{3}COOH=369.3-101.7+71.7=339.3$

so

$\alpha =14.3/339.3=0.041$

so hydrogen ion conc.$=c\alpha =0.01\times 0.041=4\times {10}^{-4}$