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Standard XII

Chemistry

Characteristics of Equilibrium Constant

At 298 K eq...

Question

At $298 K$ equilibrium constant $K_{1}$ and $K_{2}$ of following reaction $S O_{2} (g) + 1 / 2 O_{2} (g) ⇌ S O_{3} (g)$ ----- (1)
$2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)$ -------- (2)
The relation between $K_{1}$ and $K_{2}$ is :

K_{1} = K_{2}

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K_{2} = {K_{1}}^{2}

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K_{2} = 1 / {K_{1}}^{2}

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K_{2} = 1 / K_{1}

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Solution

The correct option is B $K_{2} = 1 / {K_{1}}^{2}$
$S O_{2} (g) + 1 / 2 O_{2} (g) ⇌ S O_{3} (g)$
$K_{1} = [S O_{3}] / [S O_{2}] [O_{2}]^{1 / 2}$
$2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)$
$K_{2} = [O_{2}] [S O_{2}]^{2} / [S O_{3}]^{2}$
so,
$K_{2} = 1 / {K_{1}}^{2}$

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At 298K equilibrium constant K1 and K2 of following reaction SO2(g)+1/2O2(g)⇌SO3(g) ----- (1)2SO3(g)⇌2SO2(g)+O2(g) -------- (2)The relation between K1 and K2 is :

The correct option is B K2=1/K12SO2(g)+1/2O2(g)⇌SO3(g)K1=[SO3]/[SO2][O2]1/22SO3(g)⇌2SO2(g)+O2(g)K2=[O2][SO2]2/[SO3]2so,K2=1/K12

At $298 K$ equilibrium constant $K_{1}$ and $K_{2}$ of following reaction $S O_{2} (g) + 1 / 2 O_{2} (g) ⇌ S O_{3} (g)$ ----- (1)
$2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)$ -------- (2)
The relation between $K_{1}$ and $K_{2}$ is :

The correct option is B $K_{2} = 1 / {K_{1}}^{2}$
$S O_{2} (g) + 1 / 2 O_{2} (g) ⇌ S O_{3} (g)$
$K_{1} = [S O_{3}] / [S O_{2}] [O_{2}]^{1 / 2}$
$2 S O_{3} (g) ⇌ 2 S O_{2} (g) + O_{2} (g)$
$K_{2} = [O_{2}] [S O_{2}]^{2} / [S O_{3}]^{2}$
so,
$K_{2} = 1 / {K_{1}}^{2}$