At 298K, the enthalpy of fusion of a solid (X) is 2.8KJ mol−1 and the enthalpy of vaporisation of the liquid (X) is 98.2KJmol−1. The enthalpy of sublimation of the substance (X) in KJmol−1 is . (in nearest integer)
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Solution
ΔsubH=ΔfusH+ΔvapH (These values should be at a given temperature) ΔsubH=98.2+2.8ΔsubH=101KJmol−1