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Calorimetry

At 298 K, the...

Question

At $298 K$ , the enthalpy of fusion of a solid $(X)$ is $2.8 {KJ mol}^{- 1}$ and the enthalpy of vaporisation of the liquid $(X)$ is $98.2 K J {mol}^{- 1}$ . The enthalpy of sublimation of the substance $(X)$ in $K J {mol}^{- 1}$ is . (in nearest integer)

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Solution

$Δ_{sub} H = Δ_{fus} H + Δ_{vap} H$ (These values should be at a given temperature)
$Δ_{sub} H = 98.2 + 2.8 Δ_{sub} H = 101 K J {mol}^{- 1}$

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