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Question

At $$3.40$$, the hour hand and the minute hand of a clock form an angle of:


A
120o
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B
125o
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C
130o
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D
135o
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Solution

The correct option is C $${130}^{o}$$
Angle traced  by hour hand in $$12hrs={360}^{o}$$.
Angle traced by it in $$\cfrac { 11 }{ 3 } hrs={ \left( \cfrac { 360 }{ 12 } \times \cfrac { 11 }{ 3 }  \right)  }^{ o }={ 110 }^{ o }$$
Angle traced by minute hand in $$60min={360}^{o}$$.
Angle traced by it in $${ 40min.=\left( \cfrac { 360 }{ 60 } \times 40 \right)  }^{ o }={ 240 }^{ o }$$.
$$\therefore$$ Required angle $${ \left( 240-110 \right)  }^{ o }={ 130 }^{ o }$$.

Logical Reasoning

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