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Degree of Dissociation

At 30∘C,Kp fo...

Question

At $30^{\circ} C, K_{p}$ for the dissociation reaction:
$S O_{2} C l_{2} (g) ⇋ S O_{2} (g) + C l_{2} (g) i s 2.9 x 10^{- 2}$ ~atm. If the total pressure is 1 atm, the degree of dissociation of $S O_{2} C l_{2} i s (a s s u m e 1 - α^{2} = 1)$

85 %

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12 %

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17 %

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35 %

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Solution

The correct option is C $17 %$
Correct option is c).
$\begin{matrix} S O_{2} C l_{2} (g) ⇋ & S O_{2} (g) + & C l_{2} (g) 1 & 0 & 0 1 - α & α & α \end{matrix}$
Total moles = $1 + α$
$P s o_{2} C l_{2} = 1 - α / 1 + α, P s o_{2} = α / 1 + α, P c l_{2} = α / 1 + α$
$K_{p} = (α / 1 + α)^{2} / (1 - α / 1 + α) = α^{2} / 1 - α^{2} \approx α^{2}$
$α = \sqrt{K p} = (2.9 \times 10^{- 2} = 0.17, i . e ., 17 %$

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