Question

At ${30}^{\circ }C$, the solubility of $A{g}_{2}C{O}_3(K_{sp}=8\times {10}^{-2})$ will be maximum in:

• A. $0.05MN{a}_{2}C{O}_3$
• B. $0.05MAgN{O}_3$
• C. Pure water
• D. $0.05N{H}_3$

Answer 1

The correct option is D $0.05N{H}_3$

When ${Ag}_2{CO}_3$ reacts with Ammonia, it forms a soluble complex i.e,

${Ag}_2{CO}_3\to {2Ag}^{+}+{CO}_3^{2-}$

${2Ag}^{+}+4{NH}_3\to 2{\left[{Ag\left[{NH}_3\right]}_2\right]}^{+}$

$(\ast )$ Here due to formation of silver complex, Ammonia shifts the solubility equilibria in forward direction which inturn increase the solubility.

$\Rightarrow$ Answer $D$