From K=Ae^ Ea/RT , We know that K_1K_2=T_1T_2 #160; #160; #160; #160;( K = number of molecules, T = Temperature) ⇒5025=300T_2 ...

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At 300 K, 5...

Question

At $300 K, 50$ of molecule collide with energy grater than or equal to $E_{a}$ . At what temperature, $25$ molecule will have energy greater than or equal to $E_{a}$ .

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Solution

From $K = A e^{- E a / R T}$ , We know that $\frac{K_{1}}{K_{2}} = \frac{T_{1}}{T_{2}}$ ( $K$ = number of molecules, $T$ = Temperature)
$\Rightarrow \frac{50}{25} = \frac{300}{T_{2}}$
$\Rightarrow T_{2} = 150 K$

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