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Empirical & Molecular Formula

At 300 K and ...

Question

At $300 K$ and 1 atmospheric pressure, $10 m L$ of a hydrocarbon required $55 m L$ of $O_{2}$ for complete combustion and $40 m L$ of $C O_{2}$ is formed. The formula of the hydrocarbon is:

A

C_{4} H_{8}

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B

C_{4} H_{7} C l

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C

C_{4} H_{10}

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D

C_{4} H_{6}

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Solution

The correct option is D $C_{4} H_{6}$
General reaction for combustion of hydrocarbons:

$C_{x} H_{y} + (x + \frac{y}{4}) O_{2} \to x C O_{2} + \frac{y}{2} H_{2} O 10 m L 10 (x + \frac{y}{4}) m L 10 x m L$

By given data,
$10 (x + \frac{y}{4}) = 55$
and
$10 x = 40$
Solving the above two equations:
$x = 4, y = 6 \Rightarrow C_{4} H_{6}$
Hence, option D is correct.

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