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Question

At 300K, the number of molecules possessing most probable velocity are 100. At 400K the number of such molecules will be:

A
65
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B
100
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C
110
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D
120
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Solution

The correct option is A 65
From Maxwell Boltzmann's distribution,
f(c)=4πc2(m2πkBT)3/2emc22kBT
here f(c) is the form of function defines the distribution of the gas molecules moving at different speeds.

so, no of particle at 400K moving with most probable speed /no of particle at 300K moving with most probable speed = (300/400)3/2

or, no of particle at 400K moving with most probable speed =(300/400)3/2×100=64.95 65


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