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Question

At 300 K, two solutions of glucose in water of concentration 0.01 M and 0.001 M are separated by semipemeable membrane. Pressure needs to be applied on solution, to prevent osmosis Calculate the magnitude of this applied pressure.

A
P=0.111atm
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B
P=0.222atm
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C
P=0.264atm
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D
P=0.528atm
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Solution

The correct option is B P=0.222atm
The osmotic pressure, Π=CRT=(0.010.001)×0.08206×300=0.222 atm
Here, Π is the osmotic pressure, C is the difference in the concentration of two solutions, R is the ideal gas constant and T is the absolute temperature.

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