At 300K, when a solute is added to a solvent its vapour pressure over mercury reduces from 50 mm to 45 mm. The value of mole fraction of solute will be:

0.005

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0.010

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0.100

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0.900

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Solution

The correct option is C 0.100

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Similar questions

At 300K, when a solute is added to a solvent its vapour pressure over mercury reduces from 50 mm to 45 mm. The value of mole fraction of solute will be:

On adding solute to a pure solvent, having vapour pressure 0.80 atm, vapour pressure reduces to 0.60 atm. Mole fraction of solute is

Q. The vapour pressure of a solvent decreased by

10 m m

of mercury when a non-volatile solute was added to the solvent. The mole fraction of the solute in the solution is

0.2

. What should be the mole fraction of the solvent, if the decrease in the vapour pressure is to be

20 m m

of mercury?

Q. The vapour pressure of solvent decreased by 10 mm of mercury when a non-volatile solute was added to solvent. The mole fraction of the solute in the solution is 0.2. What would be the mole fraction of the solvent if the decrease in the vapour pressure is to be 20 mm of mercury?

The vapour pressure of pure liquid solvent

A

0.80 a t m

when a non-volatile solute

B

is added to the solvent its vapours pressure falls to

0.60 a t m

. Mole fraction of solute

B

in the solution is:

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