At $363 K$ , the vapour pressure of $A$ is $21$ $k P a$ and that of $B$ is $18$ $k P a$ . One mole of $A$ and $2$ moles of $B$ are mixed. Assuming that this solution is ideal, the vapour pressure of the mixture is $k P a$ . (Round off to the nearest integer).

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Solution

$X_{A} = \frac{1}{1 + 2} = \frac{1}{3} X_{A} = \frac{2}{3}$

$P_{A}^{0}$ = $21$ $k P a$ $P_{B}^{0}$ = $18$ $k P a$

$P_{total} = P_{A}^{0} X_{A} + P_{B}^{0} X_{B}$

$= 21 \times \frac{1}{3} + 18 \times \frac{2}{3}$
$= 7 + 12$
$= 19$ $k P a$

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At 363 K, the vapour pressure of A is 21 kPa and that of B is 18 kPa. One mole of A and 2 moles of B are mixed. Assuming that this solution is ideal, the vapour pressure of the mixture is kPa. (Round off to the nearest integer).

XA=11+2=13XA=23 P0A = 21 kPa P0B = 18 kPa Ptotal=P0AXA+P0BXB =21×13+18×23 =7+12 =19 kPa

At $363 K$ , the vapour pressure of $A$ is $21$ $k P a$ and that of $B$ is $18$ $k P a$ . One mole of $A$ and $2$ moles of $B$ are mixed. Assuming that this solution is ideal, the vapour pressure of the mixture is $k P a$ . (Round off to the nearest integer).

$X_{A} = \frac{1}{1 + 2} = \frac{1}{3} X_{A} = \frac{2}{3}$

$P_{A}^{0}$ = $21$ $k P a$ $P_{B}^{0}$ = $18$ $k P a$

$P_{total} = P_{A}^{0} X_{A} + P_{B}^{0} X_{B}$

$= 21 \times \frac{1}{3} + 18 \times \frac{2}{3}$
$= 7 + 12$
$= 19$ $k P a$