CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

At 373k the half-life period for the thermal decomposition of N2O5 is 4.6 sec and is independent of the initial pressure of N2O5. Calculate the specific rate constant of this temperature.

A
K=0.1507 s1
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
K=0.3014 s1
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
K=0.1507 s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
K=0.3014 s2
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C K=0.1507 s1
Decomposition of N2O5 is 1st Order Reaction.

So, K=0.693t1/2

K=0.1507 s1

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Rate Constant
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon