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Question

At 380oC, the half life period for the first order decomposition of H2O2 is 360 min. The energy of activation of the reaction is 200 kJ mol1. Calculate the time required for 75% decomposition at 450oC.

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Solution

We have, K1=0.693360min1at 653 K, Ea=200×103 J,

K2=? at 723K,R=8.314J
from 2.303log10(K2K1)=(EaR)[(T2T1)T1T2]

K2=0.068min1
Now, t=(2.3030.068)log10(10025)
t=20.39minutes


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