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Question

At 450K,KP=2.0×1010bar for the given reaction at equilibrium.
2SO2(g)+O2(g)2SO3(g)
What is Kc, at this temperature?

A
7.4×1011Lmol1
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B
7.4×1011Lmol1
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C
3.7×1011Lmol1
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D
3.7×1011Lmol1
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Solution

The correct option is A 7.4×1011Lmol1
The relationship between Kp and Kc is Kp=Kc(RT)Δn.
For the reaction 2SO2(g)+O2(g)2SO3(g), the value of Δn is 2+12=1.
Substitute this value in the above expression.
Kp=Kc(RT)Δn=Kc(RT)1.
But KP=2.0×1010/bar,R=0.082L atm /mol. K,T=450K.
Substitute values in the above expression.
2.0×1010/bar=Kc(0.082×450)1.
Kc=7.4×1011Lmol1.

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