At 473 K- Kc for the reaction PCl5g- PCl3g - Cl2g is 8-3 - 10-3- What will be the value of Kc for the formation of PCl5 at the same temperature-

The correct option is C 120.48 PCl_5⇌ PCl_3 + Cl_2, K_c = 8.3× 10^ 3 The value of K_c for the formation of PCl_5 is the backward or the r ...

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Standard XII

Chemistry

Characteristics of Equilibrium Constant

At 473 K, K...

Question

At $473 K, K_{c}$ for the reaction
$P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)} i s 8.3 \times 10^{- 3}$ . What will be the value of $K_{c}$ for the formation of $P C l_{5}$ at the same temperature?

8.3 \times 10^{3}

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120.48

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8.3 \times 10^{- 3}

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240.8

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Solution

The correct option is C $120.48$
$P C l_{5} ⇌ P C l_{3} + C l_{2}, K_{c} = 8.3 \times 10^{- 3}$
The value of $K_{c}$ for the formation of $P C l_{5}$ is the backward or the reverse reaction, for this the equilibrium constant
$K_{c}^{'} = \frac{1}{K_{c}}$

$K_{c}^{'} = \frac{1}{8.3 \times 10^{- 3}}$

$K_{c}^{'} = \frac{1}{0.0083} = 120.48$

$∴$ the equilibrium constant for the formation of $P C l_{5}, K_{c}^{'} = 120.48$

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Similar questions

At 473 K, equilibrium constant Kc for decomposition of phosphorus pentachloride, $P C l_{5} i s 8.3 \times 10^{- 3}$ . If decomposition is depicted as,
$P C l_{5} (g) \leftrightarrow P C l_{3} (g) + C l_{2} (g) Δ_{r} H^{\circ} = 124.0 k J m o l^{- 1}$

Write an expression for $K_{c}$ for the reaction.

What is the value of $K_{c}$ for the reverse reaction at the same termperature?

What would be the effect on $K_{c}$ if
(i) more $P C l_{5}$ is added
(ii) pressure is increased?
(iii) The temperature is increased?

At 473 K, equilibrium constant K_cfor decomposition of phosphorus pentachloride, PCl₅ is 8.3 ×10^-3. If decomposition is depicted as,

_rH° = 124.0 kJmol^–1

a) Write an expression for K_cfor the reaction.

b) What is the value of K_cfor the reverse reaction at the same temperature?

c) What would be the effect on K_c if (i) more PCl₅ is added (ii) pressure is increased? (iii) The temperature is increased?

Q. At 473 K, equilibrium constant

K_{c}

for decomposition of phosphorus pentachloride,

{P C l}_{5}

8.3 \times 10^{- 3}

. If decomposition is depicted as,

{P C l}_{5} (g) ⇌ {P C l}_{3} (g) + {C l}_{2} (g)

Δ_{r} H^{⊖} = 124.0 k J {m o l}^{- 1}

(a) Write an expression for

K_{c}

for the reaction.
(b) What is the value of

K_{c}

for the reverse reaction at the same temperature?
(c) What would be the effect on

K_{c}

if (i) more

{P C l}_{5}

is added (ii) pressure is increased (iii) the temperature is increased ?

Q. At

473

K, equilibrium constant,

K_{c}

for decomposition of phosphorus pentachloride,

P C l_{5}

8.3 \times 10^{- 3}

. If decomposition is depicted as:

P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)}; △_{r} H^{0} = 124.0 k m o l^{- 1}

what would be the effect on reaction if the temperature is increased?

A sample of pure PCl₅ was introduced into an evacuated vessel at 473 K. After equilibrium was attained, concentration of PCl₅ was found to be 0.5 × 10^–1 mol L^–1. If value of K_c is 8.3 × 10^–3, what are the concentrations of PCl₃ and Cl₂ at equilibrium?

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At 473K,Kc for the reactionPCl5(g)⇌PCl3(g)+Cl2(g) is 8.3×10−3. What will be the value of Kc for the formation of PCl5 at the same temperature?

The correct option is C 120.48PCl5⇌PCl3+Cl2,Kc=8.3×10−3The value of Kc for the formation of PCl5 is the backward or the reverse reaction, for this the equilibrium constantK′c=1KcK′c=18.3×10−3K′c=10.0083=120.48∴ the equilibrium constant for the formation of PCl5,K′c=120.48

At $473 K, K_{c}$ for the reaction
$P C l_{5 (g)} ⇌ P C l_{3 (g)} + C l_{2 (g)} i s 8.3 \times 10^{- 3}$ . What will be the value of $K_{c}$ for the formation of $P C l_{5}$ at the same temperature?