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Question

At 540 K,0.10 mole of PCl5 are heated in 0.8 L flask. The pressure of the equilibrium mixture is found to be 1.0 atm. Calculate Kp and Kc for the reaction.

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Solution

PCl5PCl3+Cl2
Initial0.1 mol
At eqm.0.1xxx
Total no. of moles at eqm. =0.1+x
PV=nRT
i.e. n=dfracPVRT=1×80.0821×540=0.18
0.1+x=0.18 or x=0.08
Kc=(0.08/8)(0.08/8)(0.02/8)=0.04
Kp=Kc(RT)Δn=0.04(0.0821×540)1=1.77

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