Question

At ${60}^o$C and 1 atm, $N_2{O}_2$ is 50% dissociated into $N{O}_2$ then $K_p$ is

• A. 1.33 atm
• B. 2 atm
• C. 2.67 atm
• D. 3 atm

Answer 1

The correct option is B 2 atm


$N_2{O}_4$ is 50% dissociated, so $\alpha =\frac{1}{2}$

$K_p=\frac{p_{N{O}_2}^2}{p_{N_2{O}_4}}=\frac{{(2\times \frac{1}{2})}^2}{(1-\frac{1}{2})}=2atm$
Hence, option (b) is correct.