At 600∘C , Kp for the following reaction is 1 atm X(g)⇌Y(g)+Z(g). At equilibrium, 50% of X(g) is dissociated. The total pressure of the equilibrium system is P atm. What is the partial pressure (in atm) of X(g) at equilibrium ?
A
1
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B
4
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C
2
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D
0.5
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Solution
The correct option is D 1 X(g)⇌Y(g)+Z(g)
t = 0 PX 0 0 At eq. 0.5PX0.5PX0.5PX Kp=0.5PX=1
=>PX=2 Partial pressure of X at equilibrium =0.5PX=1atm