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Question

At 672C and one atmosphere, SO3 is partially dissociated into SO2 and O2. SO3(g)SO2(g)+12O2(g) . If the density of the equilibrium mixture is 0.925 g/litre, then what is the degree of dissociation?

A
0.74
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B
0.34
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C
0.68
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D
0.64
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Solution

The correct option is D 0.34
M=ρRTP
M= Molar mass of an ideal gas.
P= Density at pressure P and temperature T.
M=0.925×0.021×(627+273)1
M=68.36g/mol
2SO3(g)2SO2(g)+O2(g)
1x x x2
1x+x+x2=1+x2
Mole fraction of SO3=1x1+x2=1x1+x2
XSO2=x1+x2; XO2=x21+x2
68.36=⎜ ⎜1x1+x2⎟ ⎟80.066+x(1+x2)64.066+⎜ ⎜x21+x2⎟ ⎟32.0
From that we will get x=0.35.
Degree of dissociation α=0.35 .

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