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Question

At 700K, the equilibrium constant, KP, for the reaction 2SO3(g)2SO2(g)+O2(g) is 1.8×103 kPa. The value of Kc for the above reaction at the same temperature in moles per m3 would be:

A
1.1×107
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B
3.1×104
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C
6.2×107
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D
9.3×107
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Solution

The correct option is B 3.1×104
2SO3(g)2SO2(g)+O2(g)
As we know that,
Kp=Kc(RT)Δn
whereas,
Given that:-
Kp=1.8×103kPa=1.8(Given)
T=700K(Given)
R=8.314×103m3kPaK1mol1
Kc=?
Δn= change in no. of moles = no. of moles of product- no. of moles of reactant
Δn=npnr=(2+1)(2)=1
1.8×103=Kc×(8.314×103×700)1
Kc=1.8×1038.314×103×700=3.1×104m3mol

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