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Question

At 700K, equilibrium constant for the reaction: H2(g)+I2(g)2HI(g) is 64. If 0.5mol L1 of HI(g) is present at equilibrium at 700K, what are the concentration of H2(g) and I2(g) assuming that we initially started with HI(g) and allowed it to reach equilibrium at 700K?

A
0.0625M
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B
0.034M
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C
0.136M
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D
0.68M
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Solution

The correct option is C 0.0625M
H2(g)+I2(g)2HI(g)K=64,T=700K
2HIH2+I2K=1/64700K
a 0 0
a(1α) aα/2 aα/2
0.5 x x x be concentration
x2(0.5)2=164x=1/16
x=0.0625

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