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Effect of Catalyst

At 773 K, the...

Question

At 773 K, the equilibrium constant Kp for the reaction, N2(g) + 3 H2(g) 2NH3(g) is 49. Calculate the value of Kp for the reaction, NH3(g) 1+2 N2(g) + 3+2 H2(g) at the same temperature

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Solution

$T h e g i v e n r e a c t i o n i s N_{2} + 3 H_{2} \leftrightarrow 2 N H_{3} : K_{P} = 49 N o w r e v e r s e t h e e q u a t i o n 2 N H_{3} \leftrightarrow N_{2} + 3 H_{2} : {K_{P}}^{'} = \frac{1}{49} N o w d i v i d e t h e e q u a t i o n b y 2 . N H_{3} \leftrightarrow \frac{1}{2} N_{2} + \frac{3}{2} H_{2} : {K_{P}}^{''} = \sqrt{K_{P}'} = \sqrt{\frac{1}{49}} = \frac{1}{7} = 0.1429$

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