At 80∘C, the vapour pressure of a pure liquid A is 520mm Hg and that of a pure liquid of B is 1000mm Hg. If the ideal mixture of liquids A and B boils at 80∘C and 1 atm pressure, the amount of solution A in the mixture is: (1 atm = 760 mm Hg)
A
50mol%
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B
52mol%
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C
34mol%
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D
48mol%
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Solution
The correct option is A50mol% We know that, PT=PoAxA+PoBxB xAandxB mole fraction of A and B 760=520xA+(1000(1−xA) xA=12=0.5
So, 50 mol % of A is present in the mixture.